Chicken Scarpariello
Chicken Scarpariello is a flavorful and savory Italian-American dish that features tender chicken cooked in a rich, tangy sauce. The dish is known for its bold combination of flavors, which often includes a mix of garlic, peppers, white wine, and sometimes olives, creating a delicious balance of heat, acidity, and richness.
Ingredients
- 1¼ pounds skinless, boneless chicken breast halves
- 3 tablespoons all-purpose flour
- 2 tablespoons olive oil
- 2 teaspoons butter
- 2 tablespoons shallots, minced
- 2 cloves garlic, minced
- 1 cup water
- ½ cup white wine
- 1 cube chicken bouillon
- ½ teaspoon dried rosemary, crushed
- ¼ teaspoon salt
- 1 pinch ground black pepper
Instructions
- Collect all the necessary ingredients before you begin, ensuring everything is ready for the cooking process. This step helps streamline the preparation and ensures a smooth cooking experience.
- Slice the chicken breasts into 1 x 3-inch strips, then lightly coat them in flour, ensuring each piece is evenly covered. This will help create a crispy exterior when cooked.
- In a 10-inch skillet, heat the oil and butter together. Add the floured chicken strips and cook, turning occasionally, until they are golden brown on all sides, about 3 to 4 minutes. Using tongs, carefully remove the chicken from the skillet and set it aside to keep warm.
- In the same skillet, add the minced shallots and garlic. Sauté for about a minute, or until they become fragrant and softened.
- Pour in the water, wine, broth mix, and seasonings, stirring to combine. Let the mixture cook, stirring occasionally, until the liquid is reduced by half, about 3 to 4 minutes.
- Add the chicken back into the skillet and cook for another 2 to 3 minutes, allowing the sauce to thicken and the chicken to heat through completely.